NIMCET 2018 Logical Reasoning PYQ — A body travels from A to B in 10s with a speed of 50 km/h and ret… | Mathem Solvex | Mathem Solvex
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NIMCET 2018 — Logical Reasoning PYQ
NIMCET | Logical Reasoning | 2018
A body travels from A to B in 10s with a speed of 50 km/h and returns with a speed of 100 km/h in 5s. The average speed and the average velocity for the whole journey is
Choose the correct answer:
A.
17.5 m/s - 1, 0 km/h
B.
16.5 m/s - 1, 0 km/h
C.
15.5 m/s - 1, 0 km/h
D.
18.5 m/s - 1, 0 km/h
(Correct Answer)
Correct Answer:
18.5 m/s - 1, 0 km/h
Explanation
Correct Option - 4 Given: From A to B in 10s with a speed of 50 km/h. Returns with a speed of 100 km/h in 5s Formula Used: Speed = distance/time Average speed = total distance/total time m/s = 5/18 × km/hr Calculation: From A to B in 10s with a speed of 50 km/h. m/s = 5/18 × km/hr ⇒ 5/18 ×50 ⇒ 125/9m/s Distance = speed × time ⇒ Distance = 125/9 × 10 ⇒ Distance = 1250/9 meters Returns with a speed of 100 km/h in 5s m/s = 5/18 × km/hr ⇒ 5/18 ×100 ⇒ 250/9m/s Distance = speed × time ⇒ Distance = 250/9 × 5 ⇒ Distance = 1250/9 meters Average speed = total distance/total time
⇒Average speed = 2500/(15×9) ⇒Average speed = 2500/135 ⇒Average speed = 18.5m/s ∴ Average speed is 18.5m/s
Explanation
Correct Option - 4 Given: From A to B in 10s with a speed of 50 km/h. Returns with a speed of 100 km/h in 5s Formula Used: Speed = distance/time Average speed = total distance/total time m/s = 5/18 × km/hr Calculation: From A to B in 10s with a speed of 50 km/h. m/s = 5/18 × km/hr ⇒ 5/18 ×50 ⇒ 125/9m/s Distance = speed × time ⇒ Distance = 125/9 × 10 ⇒ Distance = 1250/9 meters Returns with a speed of 100 km/h in 5s m/s = 5/18 × km/hr ⇒ 5/18 ×100 ⇒ 250/9m/s Distance = speed × time ⇒ Distance = 250/9 × 5 ⇒ Distance = 1250/9 meters Average speed = total distance/total time
⇒Average speed = 2500/(15×9) ⇒Average speed = 2500/135 ⇒Average speed = 18.5m/s ∴ Average speed is 18.5m/s