NIMCET 2019 — Mathematics PYQ

Q: How do I solve NIMCET 2019 Mathematics questions?

Practice NIMCET 2019 Mathematics previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

Q: What is the difficulty level of NIMCET Mathematics questions?

NIMCET Mathematics questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Q: Are NIMCET previous year papers available for free?

Yes. Mathem Solvex provides free access to NIMCET previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

Question

NIMCET 2019 — Mathematics PYQ

NIMCET | Mathematics | 2019

If $x, 2 x + 2, 3 x + 3$ are the first three terms of a geometric progression, then 4th term in the geometric progression is

Choose the correct answer:

Explanation

Concept:
If a, b, c are in GP than $r = \frac{b}{a} = \frac{c}{b}$

If first term of GP is a and common ratio is r than nth term of GP is given by $a r^{n - 1}$

Calculation:

Given: x, 2x + 2, 3x + 3 are the first three terms of a geometric progression, then

$\frac{2 x + 2}{x} = \frac{3 x + 3}{2 x + 2}$

$\frac{2 x + 2}{x} = \frac{3}{2}$

$4 x + 4 = 3 x \Rightarrow x = - 4 = a$

$r = \frac{c}{b} = \frac{3 x + 3}{2 x + 2} = \frac{3}{2}$

4th term in the geometric progression is $T_{4} = a r^{n - 1}$

$T_{4} = (- 4) (\frac{3}{2})^{4 - 1} = - 13.5$