How many minimum numbers of colours will be required to paint all the sides of a cube without the adjacent sideshaving the same colours?
Explanation
Step 1: Understand the geometry of a cube
A standard cube has a total of 6 faces. These faces exist in pairs of opposite sides. Specifically:
Step 2: Understand the adjacency rule
The problem states that no two adjacent sides can have the same color.
On a cube, each face is adjacent to exactly 4 other faces.
The only face that is not adjacent to a given face is its opposite face.
Step 3: Calculate the minimum number of colors
To minimize the number of colors used, we can paint opposite faces with the same color, because opposite faces do not share any common edges (they are not adjacent).
Let the three pairs of opposite faces be:
Top and Bottom → Color 1
Front and Back → Color 2
Left and Right → Color 3
Therefore, the mathematical relation for the minimum number of colors N required can be expressed as:
N=Faces per non-adjacent setTotal faces
N=26=3
Thus, a minimum of 3 colors are required to paint the cube under the given conditions.
Correct Option: A