Four students A, B, C and 0 distributed 30 marbles among themselves. No two students got equal number of marbles.No student got more than 10 marbles. No student got less than 5 marbles. A and C got odd number of marbles. B andD got even number of marbles. A got more marbles than B, C got more marbles than D, B got more marbles than D.
Mean of number of marbles with B, C, D is:
Four students:
A, B, C and D
distributed 30 marbles among themselves
1) No two students got equal number of marbles.
2) No student got more than 10 marbles.
3) No student got less than 5 marbles.
4) A and C got odd number of marbles. It can be 7 or 9
5) B and D got even number of marbles.
It can be 6, 8 or 10
6) A got more marbles than B,C got more marbles than D, B got more marbles than D.
A > B > D, C > D
A (7, 9) > B (6, 8) > D (6, 8) , C (7, 9) > D (6, 8)
So, D got the least number of marbles.
∴ D got 6 marbles.
So, B got 8 marbles as B got more marbles than D.
A got 9 marbles as A got more marbles than B.
C got 7 marbles as C got more marbles than D.
Mean of number of marbles with B, C, D is = (8 + 7 + 6) ÷ 3
= 21 ÷ 3
= 7
Hence, ‘7’ is the correct answer.
