Explanation
Detailed Step-by-Step Explanation:
We need to find the value of the given expression:
bca2+cab2+abc2
Step 1: Take the Least Common Multiple (LCM)
The LCM of the denominators bc, ca, and ab is abc. Combining the fractions over a common denominator gives:
abca3+b3+c3
Step 2: Use the Algebraic Identity
We know the standard algebraic identity:
a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)
Step 3: Substitute the Given Condition
It is given that a+b+c=0. Substituting this value into the identity:
a3+b3+c3−3abc=(0)(a2+b2+c2−ab−bc−ca)
a3+b3+c3−3abc=0
a3+b3+c3=3abc
Step 4: Calculate the Final Value
Now substitute a3+b3+c3=3abc back into our simplified expression:
abc3abc=3
Conclusion:
Therefore, the value of the expression is 3, matching option C.