NIMCET 2020 — Reasoning PYQ

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Question

NIMCET 2020 — Reasoning PYQ

NIMCET | Reasoning | 2020

Three cities A, B and C are equidistant from each other. A motorist travels from A to B at 30 km/hr, from B to C at 40km/hr and from C to A at 50 km/hr. Then the average speed is:

Choose the correct answer:

Explanation

Concept:
- If the 'Speed' is constant, then the 'Distance' and the 'Time' are directly proportional to each other. It means that, if one of the quantities becomes n times, the other will also become n times.
- Speed = $\frac{D i s t an ce}{T im e}$ .
- Average Speed = $\frac{T o t a l D i s t an ce}{T o t a l T im e}$ .

Calculations:
Let's say that the distance between each pair of cities is 600 km.
From A to B:
Distance = 600 km.
Time = $\frac{D i s t an ce}{S p ee d} = \frac{600}{30} = 20$ hrs.
From B to C:
Distance = 600 km.
Time = $\frac{D i s t an ce}{S p ee d} = \frac{600}{40} = 15$ hrs.
From C to A:
Distance = 600 km.
Time = $\frac{D i s t an ce}{S p ee d} = \frac{600}{50} = 12$ hrs.
For overall journey:
Total distance = 600 + 600 + 600 = 1800 km.

Total time = 20 + 15 + 12 = 47 hrs.
Average Speed = $\frac{Total Distance}{Total Time} = \frac{1800}{47}$ = 38.29 km/hr.