Explanation
Concept
We know that, a set of which all the elements are contained in another set is known as subset
Calculations
Given, X= {4n- 3n- 1: nϵN}, where N is the set of natural numbers.
⇒X={0,9,54,....}
and Y=\{9(n-1):n\epsilon\text{N}\}, where N is the set of natural numbers,
⇒Y={0,9,18,27,....}
Here, all elements of X is contained in set Y.
Hence, X is subset of Y.
X⊂Y
Hence, if x= {4n- 3n- 1: nϵN} and Y{9( n- 1) : nϵN}, where N is the set of natural numbers, then X⊂Y.