How do I solve CUET PG 2025 Mathematics questions?

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CUET PG Mathematics questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

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CUET PG 2025 Mathematics PYQ — If a, b and c in Geometric Progression and then, x, y, z are in… | Mathem Solvex

A.
Arithmetic Progression
B.
Geometric Progression
C.
$\frac{2}{y} = \frac{1}{x} + \frac{1}{z}$

Correct Answer:

$\frac{2}{y} = \frac{1}{x} + \frac{1}{z}$

Explanation

1. GP ki condition

b^2 = ac

2. Di gayi equation se relationship

a^{\frac{x}{2}} = b^{\frac{y}{2}} = c^{\frac{z}{2}} = k

Inhe $k$ ke terms mein likhne par:

$a = k^{\frac{2}{x}}$
$b = k^{\frac{2}{y}}$
$c = k^{\frac{2}{z}}$

3. Substitution

b^2 = ac

(k^{\frac{2}{y}})^2 = (k^{\frac{2}{x}}) \cdot (k^{\frac{2}{z}})

k^{\frac{4}{y}} = k^{\left(\frac{2}{x} + \frac{2}{z}\right)}

4. Powers ko compare karne par

\frac{4}{y} = \frac{2}{x} + \frac{2}{z}

\frac{2}{y} = \frac{1}{x} + \frac{1}{z}

CUET PG 2025 — Mathematics PYQ

Choose the correct answer:

Explanation

1. GP ki condition

2. Di gayi equation se relationship

3. Substitution

4. Powers ko compare karne par

Explanation

1. GP ki condition

2. Di gayi equation se relationship

3. Substitution

4. Powers ko compare karne par