CUET PG 2025 — Mathematics PYQ

Q: How do I solve CUET PG 2025 Mathematics questions?

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CUET PG Mathematics questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

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Question

CUET PG 2025 — Mathematics PYQ

CUET PG | Mathematics | 2025

$if \frac{1}{9 !} + \frac{1}{10 !} = \frac{x}{11 !} then the value of x is :$

Choose the correct answer:

Explanation

1. Di gayi equation:

\frac{1}{9!} + \frac{1}{10!} = \frac{x}{11!}

2. Left side mein common denominator ( $10!$ ) lene ke liye:

\frac{1 \times 10}{9! \times 10} + \frac{1}{10!} = \frac{x}{11!}

\frac{10}{10!} + \frac{1}{10!} = \frac{x}{11!}

3. Numerators ko jodne par:

\frac{11}{10!} = \frac{x}{11!}

4. $11!$ ko $11 \times 10!$ ke roop mein likhne par:

\frac{11}{10!} = \frac{x}{11 \times 10!}

5. Dono taraf se $10!$ cancel karne par:

11 = \frac{x}{11}

6. $x$ ki value nikalne ke liye cross-multiplication:

x = 11 \times 11

x = 121