CUET PG 2025 — Mathematics PYQ

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Question

CUET PG 2025 — Mathematics PYQ

CUET PG | Mathematics | 2025

$< b r > 1 b c < b r > a (b + c) am p; 1 am p; c a am p; b (c + a) am p; 1 am p; ab am p; c (a + b) nb s p; < b r >$

Choose the correct answer:

Explanation

\Delta = \begin{vmatrix} 1 & 1 & 1 \\ bc & ca & ab \\ ab+ac & bc+ab & ac+bc \end{vmatrix}

Operation $R_3 \to R_3 + R_2$ :

\Delta = \begin{vmatrix} 1 & 1 & 1 \\ bc & ca & ab \\ ab+bc+ca & ab+bc+ca & ab+bc+ca \end{vmatrix}

$R_3$ se $(ab+bc+ca)$ common lene par:

\Delta = (ab+bc+ca) \begin{vmatrix} 1 & 1 & 1 \\ bc & ca & ab \\ 1 & 1 & 1 \end{vmatrix}

Kyunki $R_1$ aur $R_3$ same hain ( $R_1 = R_3$ ), isliye determinant ki value $0$ hogi:

\Delta = (ab+bc+ca) \times 0 = 0

Answer: Factor form mein value $ab+bc+ca$ hai, lekin final result $0$ hai.