CUET PG 2025 — Computer PYQ

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Question

CUET PG 2025 — Computer PYQ

CUET PG | Computer | 2025

Minimum number of 2:1 Multiplexers required to design a 16:1 Multiplexer is?

Choose the correct answer:

Explanation

To implement $2^{n} \times 1$ MUX using $2 \times 1$ MUX, the total number of $2 \times 1$ MUX required is $(2^{n} - 1)$ .

∴ The number of $2 \times 1$ multiplexer required to implement $16 \times 1$ MUX will be:

$n = 16 - 1 = 15$

Or we can follow the below steps to calculate the same:

$1^{s t}$ stage $= \frac{16}{2} = 8$

$2^{n d}$ stage $= \frac{8}{2} = 4$

$3^{r d}$ stage $= \frac{4}{2} = 2$

$4^{t h}$ stage $= \frac{2}{2} = 1$

The sum will give the total number of MUX required to implement $16 \times 1$ multiplexer using $2 \times 1$ , i.e.

$n = 8 + 4 + 2 + 1 = 15$