Solution
1. Substitution
Let's set the entire "top" tower as our variable u:
2. Differentiating both sides
Recall that the derivative of af(x) is af(x)⋅ln(a)⋅f′(x). Applying the chain rule repeatedly:
dxdu=333x⋅ln(3)⋅dxd(33x)
dxdu=333x⋅ln(3)⋅(33x⋅ln(3)⋅dxd(3x))
dxdu=333x⋅ln(3)⋅33x⋅ln(3)⋅(3x⋅ln(3))
3. Simplify the expression
Combining the ln(3) terms, we get:
du=(333x⋅33x⋅3x)⋅(ln3)3dx
Now, notice that the expression in the parentheses is exactly what we have in our original integral! So, we can rewrite it as:
4. Substitute back into the Integral
The integral now becomes very simple:
5. Integrate and Final Result
Since (ln3)31 is just a constant:
Substituting u=333x back:
Final Answer
∫333x⋅33x⋅3xdx=(ln3)3333x+C