NIMCET 2023 Reasoning PYQ — A can do a piece of work in 10 days and B can do a work in 20 day… | Mathem Solvex | Mathem Solvex
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NIMCET 2023 — Reasoning PYQ
NIMCET | Reasoning | 2023
A can do a piece of work in 10 days and B can do a work in 20 days after 4 days B left and C joins then A and C to work together in 2 days. In how many days C alone do the work
Choose the correct answer:
A.
12 days
B.
15 days
C.
10 days
(Correct Answer)
D.
20 days
Correct Answer:
10 days
Explanation
Concept: Let Pipe A can fill the tank in x hrs. Pipe A can fill a tank in 1 hrs = 1/x Calculation: A can complete the work in = 10 days A's 1 day's work = 1/10 B can complete the work in = 20 days B's 1 day's work = 1/20 (A + B + C) can complete the work in = 4 days (A + B + C)'s 1 day's work = 1/4 Let, C can complete the work in = x days C's 1 day's work = 1/x According to problem, (1/10)+(1/20)+(1/x)=(1/4) <br>(1/x)=(5−2−1)/20 1/x=1/10 <br>∴x=10 ∴ C alone can complete the work in 10 days.
Explanation
Concept: Let Pipe A can fill the tank in x hrs. Pipe A can fill a tank in 1 hrs = 1/x Calculation: A can complete the work in = 10 days A's 1 day's work = 1/10 B can complete the work in = 20 days B's 1 day's work = 1/20 (A + B + C) can complete the work in = 4 days (A + B + C)'s 1 day's work = 1/4 Let, C can complete the work in = x days C's 1 day's work = 1/x According to problem, (1/10)+(1/20)+(1/x)=(1/4) <br>(1/x)=(5−2−1)/20 1/x=1/10 <br>∴x=10 ∴ C alone can complete the work in 10 days.
