1. Factoring the Expressions
First, let's factor the quadratic expressions inside the absolute values:
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x2−4x=x(x−4)
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x2−5x+6=(x−2)(x−3)
The given equation is:
2. Identifying the Relationship between Terms
Let's define:
a=x2−5x+6
b=x−6
If we add a and b:
a+b=(x2−5x+6)+(x−6)=x2−4x
Now, substitute these back into the original equation:
Rewriting this:
3. Applying the Absolute Value Property
The property ∣a+b∣=∣a∣+∣b∣ holds true if and only if a and b have the same sign (both non-negative or both non-positive). Mathematically:
Substitute the values of a and b:
4. Solving the Inequality (Wavy Curve Method)
To solve (x−2)(x−3)(x−6)≥0, we find the critical points: x=2,3,6.
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For x≥6: The expression is (+)(+)(+)≥0 (True)
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For 3≤x≤6: The expression is (+)(+)(−)≥0 (False)
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For 2≤x≤3: The expression is (+)(−)(−)≥0 (True)
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For x≤2: The expression is (−)(−)(−)≥0 (False)
Thus, the solution set is x∈[2,3]∪[6,∞).
Final Answer
The value of x lies in the interval [2,3]∪[6,∞).
Correct Option: (B)