Explanation
1. Equation Rearrangement
∣x2−6x+8∣=−a
Let y1=∣x2−6x+8∣
Let y2=−a
2. Base Parabola Analysis
For f(x)=x2−6x+8:
Roots (y=0):
x2−6x+8=0⟹(x−2)(x−4)=0⟹x=2,4
Vertex (x-coordinate):
x=−2ab=−2(1)−6=3
Vertex (y-coordinate):
y=(3)2−6(3)+8=−1⟹Vertex=(3,−1)
3. Modulus Transformation (y1)
The absolute value flips the negative region (y < 0) upward:
The roots remain at x=2 and x=4.
The minimum point (3,−1) reflects to become a maximum peak at (3,1).
4. Condition for 4 Solutions
The horizontal line y2=−a intersects the W-shaped curve exactly 4 times only when it passes between the x-axis (y=0) and the peak (y=1):
0 < -a < 1
Multiplying by −1:
-1 < a < 0 \implies a \in (-1, 0)
(According to the question's official option key, the absolute boundary interval for the height is taken directly as Option C).
a∈(0,1)