NIMCET 2023 — Mathematics PYQ
NIMCET | Mathematics | 2023limx→1x−1x4−1=limx→1x2−k2x3−k2
Then find k.
Choose the correct answer:
- A.
8/3
(Correct Answer) - B.
4/3
- C.
2/3
- D.
1
8/3
Explanation
1. Standard Formula Used
We use the standard algebraic limit formula:
x→alimx−axn−an=n⋅an−1
2. Evaluate the Left-Hand Side (LHS)
LHS=x→1limx−1x4−14
Here, n=4 and a=1:
LHS=4⋅(1)4−1=4⋅1=4
3. Evaluate the Right-Hand Side (RHS)
RHS=x→klimx2−k2x3−k3
Divide both the numerator and the denominator by (x−k) to format it into the standard form:
RHS=limx→kx−kx2−k2limx→kx−kx3−k3
Apply the standard formula to both parts:
For the numerator: n=3,a=k⟹3k3−1=3k2
For the denominator: n=2,a=k⟹2k2−1=2k1
Simplify the fraction:
RHS=2k3k2=23k
4. Equate LHS and RHS to Find k
LHS=RHS
4=23k
Solve for k:
k=4⋅32
k=38
Explanation
1. Standard Formula Used
We use the standard algebraic limit formula:
x→alimx−axn−an=n⋅an−1
2. Evaluate the Left-Hand Side (LHS)
LHS=x→1limx−1x4−14
Here, n=4 and a=1:
LHS=4⋅(1)4−1=4⋅1=4
3. Evaluate the Right-Hand Side (RHS)
RHS=x→klimx2−k2x3−k3
Divide both the numerator and the denominator by (x−k) to format it into the standard form:
RHS=limx→kx−kx2−k2limx→kx−kx3−k3
Apply the standard formula to both parts:
For the numerator: n=3,a=k⟹3k3−1=3k2
For the denominator: n=2,a=k⟹2k2−1=2k1
Simplify the fraction:
RHS=2k3k2=23k
4. Equate LHS and RHS to Find k
LHS=RHS
4=23k
Solve for k:
k=4⋅32
k=38
