NIMCET 2023 — Mathematics PYQ
NIMCET | Mathematics | 2023Find the foci of the equation .

Find the foci of the equation x2+2x−4y2+8y−7=0.
(5±1,1)
(-1±5,1)
(Correct Answer)(-1, 5±1)
(1, -1 ±5)
(-1±5,1)
To identify the type of conic and its properties, we complete the square for both x and y.
The given equation is:
Group the x terms and y terms:
Complete the square:
For x: (x2+2x+1)
For y: −4(y2−2y+1)
Adjust the right side of the equation accordingly:
Divide the entire equation by 4 to get the standard form of a hyperbola:
Comparing this with the standard form a2(x−h)2−b2(y−k)2=1:
Center (h,k): (−1,1)
a2=4⟹a=2
b2=1⟹b=1
This is a horizontal hyperbola because the x term is positive.
For a hyperbola:
The distance from the center to each focus is c=ae:
Since the hyperbola is horizontal, the foci lie on the line y=k (the transverse axis). The coordinates are:
Final Answer:
The foci are (−1±5,1). (Option B)
To identify the type of conic and its properties, we complete the square for both x and y.
The given equation is:
Group the x terms and y terms:
Complete the square:
For x: (x2+2x+1)
For y: −4(y2−2y+1)
Adjust the right side of the equation accordingly:
Divide the entire equation by 4 to get the standard form of a hyperbola:
Comparing this with the standard form a2(x−h)2−b2(y−k)2=1:
Center (h,k): (−1,1)
a2=4⟹a=2
b2=1⟹b=1
This is a horizontal hyperbola because the x term is positive.
For a hyperbola:
The distance from the center to each focus is c=ae:
Since the hyperbola is horizontal, the foci lie on the line y=k (the transverse axis). The coordinates are:
Final Answer:
The foci are (−1±5,1). (Option B)
