NIMCET 2025 — Mathematics PYQ
NIMCET | Mathematics | 2025Let A={5n−4n−1:n∈N} and B={16(n−1):n∈N} be two sets. Which of the following is true?
Choose the correct answer:
- A.
Neither A⊂B nor B⊂A
- B.
A⊂B
(Correct Answer) - C.
B⊂A
- D.
A∩B is a finite set
A⊂B
Explanation
For n∈N,
<br>5n=(1+4)n=1+4n+k=2∑n(kn)4k<br>
Every term (kn)4k for k≥2 is divisible by 16.
Hence,
<br>5n−4n−1≡0(mod16)<br>
This means 5n−4n−1∈B for all n.
Therefore,
<br>A⊂B<br>
However, note that 32∈B, but no value of n satisfies
<br>5n−4n−1=32<br>
(since the possible values are 0,16,112,…).
Thus, B⊂A.
<br>Hence, the correct choice is (b) A⊂B.<br>
Explanation
For n∈N,
<br>5n=(1+4)n=1+4n+k=2∑n(kn)4k<br>
Every term (kn)4k for k≥2 is divisible by 16.
Hence,
<br>5n−4n−1≡0(mod16)<br>
This means 5n−4n−1∈B for all n.
Therefore,
<br>A⊂B<br>
However, note that 32∈B, but no value of n satisfies
<br>5n−4n−1=32<br>
(since the possible values are 0,16,112,…).
Thus, B⊂A.
<br>Hence, the correct choice is (b) A⊂B.<br>

