Number of permutations of the letters of the word BANGLORE such that the string ANGLE appears together in all permutations, is
Explanation
Step 1: Analyze the Given Word
The given word is BANGLORE.
Total number of letters = 8
The letters are: B, A, N, G, L, O, R, E (All letters are distinct).
Step 2: Apply the Constraint (Form the Block)
The problem states that the specific string "ANGLE" must always appear together exactly in that order.
Let us bundle the letters A, N, G, L, E together into a single block/unit:
Block=[ANGLE]
Now, list the remaining letters of the word BANGLORE:
Step 3: Count the Total Number of Units to Arrange
We now need to arrange the following units:
The single block [ANGLE]
The letter B
The letter O
The letter R
Total number of units to arrange=1+1+1+1=4 units
Step 4: Calculate the Permutations
External Arrangement: The 4 distinct units can be arranged among themselves in 4! ways.
4!=4×3×2×1=24 ways
Internal Arrangement: Because the question specifies that the string "ANGLE" must appear as a specific word/sequence, the internal order of these letters is fixed to exactly 1 way (it cannot be shuffled into "NAGLE", "ELGNA", etc.).
Step 5: Find the Final Answer
Total number of valid permutations=4!×1
Total Permutations=24
Correct Option: (A) 24