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NIMCET 2024 — Reasoning PYQ

NIMCET | Reasoning | 2024

In a recent survey of 500 employees in a company, it was found that 60% of the employees prefer coffee over tea, 25% prefer tea over coffee, and the remaining 15% have no preference. If 20% of the employees who prefer coffee are also tea drinkers, how many employees prefer only tea?

Choose the correct answer:

A.
75
B.
50
C.
65
(Correct Answer)
D.
55

Correct Answer:

Explanation

Total Employees = $500$

1. Coffee Drinkers ( $C$ ):

60\% \text{ of } 500 = \frac{60}{100} \times 500 = 300

2. Tea Drinkers ( $T$ ):

25\% \text{ of } 500 = \frac{25}{100} \times 500 = 125

3. Both (Coffee $\cap$ Tea):

20\% \text{ of Coffee Drinkers} = \frac{20}{100} \times 300 = 60

4. Only Tea:

\text{Only Tea} = \text{Total Tea} - \text{Both}

\text{Only Tea} = 125 - 60

\text{Only Tea} = 65

Correct Option:

D) 65

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Explanation

Total Employees = $500$

1. Coffee Drinkers ( $C$ ):

$60\% \text{ of } 500 = \frac{60}{100} \times 500 = 300$

2. Tea Drinkers ( $T$ ):

$25\% \text{ of } 500 = \frac{25}{100} \times 500 = 125$

3. Both (Coffee $\cap$ Tea):

$20\% \text{ of Coffee Drinkers} = \frac{20}{100} \times 300 = 60$

4. Only Tea:

$\text{Only Tea} = \text{Total Tea} - \text{Both}$

$\text{Only Tea} = 125 - 60$

$\text{Only Tea} = 65$

Correct Option:

D) 65

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