NIMCET 2020 Paper

$\frac{1}{3}{x}^{3}g(x^3)-3\int x^{4}g(x^3),dx+c$

$\frac{1}{3}{x}^{3}g(x^3)-\int x^{2}g(x^3),dx+c$

$\frac{1}{3}{x}^{3}g(x^3)-f,x^{3}g(x^3),dx+c$

None of the above